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A 50 W, 100V lamp is to be connected to ...

A 50 W, 100V lamp is to be connected to an ac mains of 200V, 50 Hz. What capacitor is essential to be put in series with the lamp?

Text Solution

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The correct Answer is:
`C=9.2 muF`
`I=50/100=0.5 Amp`
`R=V^(2)/P=(100xx100)/50=200Omega`
and `Z=200/0.5=400Omega`
`X_(C )=sqrt(Z^(2)-R^(2))=200sqrt(3)Omega implies 1/(2pifC)=200sqrt(3)`
`C=1/(100xx200sqrt(3))F=(1000)/(2pisqrt(3) muF)=50/(sqrt(3)xxpi)muF`
`=5.2 muF`
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