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A wire is bent into three circular segm...

A wire is bent into three circular segment of radius `r = 10 cm` as shown in. Each segment is a quadrant of a circle `ab` lying in the `x-y` plane, `bc` lying in the `y-z` plane and `ca` lying in the `z-x` plane.
(a) if a magnetic field `B` points in the positive `x` direction, what is the magnitude of the emf developed in the wire when `B` increases at the rate of `3 mTs^(-1)`?
(b) What is the direction of the current in the segment `bc`.

Text Solution

Verified by Experts

The correct Answer is:
`(i) 2.4xx10^(-5)V` (ii) from `c` to `b`

Flux will pass through only loop lying in `y-z` plane i.e. `bc`
(i) `phi=Bxx(pir^(2))/4`
`e=(dphi)/(dt)=(pir^(2))/4xx(dB)/(dt)`
`=3.14/4xx(0.1)^(2)xx3xx10^(-3)=2.4xx10^(-5)` volt
(ii) Flux is increasing in `x` direction so induce flux will be `(-)x` direction so current will be from `c` to `b`.
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