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Two parallel vertical metallic rails AB and CD are separated by 1m. They are connected at two ends by resistanace `(R_1) and (R_2)` as shown in fig. A horizontal metallic bar L of mass 0.2 kg slides without froction vertically down the rails under the action of gravity. THere is a uniform horizontal magnetic field of 0.6 Tesla perpendicular to the plane of the rails. It is observed taht when the teminal velocity is attained, the power dissipated in `(R_1) and (R_2)` are 0.6 watt and 1.2 watt respectively. Find the terminal velocity of the bar L and the values of `(R_1)and (R_2)`.

Text Solution

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The correct Answer is:
`V=1 ms^(-1), R_(1)=0.47Omega, R_(2)=0.30Omega`

At terminal velocity
`mg=IlB implies 0.2xx9.8=Ixx1xx0.6`
`I=1.96/0.6 Amp…(1)`
`Ie=(0.76+1.2)=1.96 …(2)`
from `(1)` and `(2)`
`1.96/0.6 e=1.96 implies e=0.6 `volt
`P_(1)=e^(2)/R_(1)=0.76`
`R_(1)=e^(2)/0.76=0.36/0.76=0.47 Omega`
`P_(2)=e^(2)/R_(2)=1.2 implies R_(2)=e^(2)/1.2=0.3 Omega`
`P=Fv implies 1.56=mg v`
`1.96=1.96v implies v=1 m//s`
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