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In the figure both cells A and B are of ...

In the figure both cells A and B are of equal emf. Find R for which potential difference across battery A will be zero, long time after the switch is closed. Internal resistance of batteries A and B `(r_1) and (r_2)` respectively`(r_(1)gtr_(2))`.

Text Solution

Verified by Experts

The correct Answer is:
`R=4/3(r_(1)-r_(2))`
After long time circuit reduces
`V=E-Ir_(1)`
`0=E-(2E)/(r_(1)+r_(2)+(3R//4))r_(1)`

`2r_(1)=r_(1)+r_(2)+(3R)/4 implies R=(4(r_(1)-r_(2)))/3`
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