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An AC voltage source of variable angular...

An AC voltage source of variable angular frequency `(omega)` and fixed amplitude `V_(0)` is connected in series with a capacitance C and an electric bulb of resistance R (inductance zero). When `(omega)` is increased

A

The bulb glows dimmer

B

The bulb glows brighter

C

Total impedence of the circuit is unchanged

D

Total impendance of the circuit increases

Text Solution

Verified by Experts

The correct Answer is:
B

Impendance `Z=[R^(2)+1/((omegaC)^(2))]^(1//2), I_(0)=V/Z` As `omega` increases, `Z` decreases. Hence the current `I_(0)` increass. Therefore, the blub glows brighter, which is choice `(B)`.
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