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The velocity of any particle is related ...

The velocity of any particle is related with its displacement As, `x = sqrt(v+1)`, Calculate acceleration at `x = 5m`.

Text Solution

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`x = sqrt(v +1) rArr x^(2) = v +1 rArr v = (x^(2) -1)`
Therefore
`a = (dv)/(dt) = (d)/(dt) (x^(2)-1) =2x(dx)/(dt) =2x v = 2x (x^(2)-1)`
at `x = 5ma = 2xx 5(25-1) = 240m//s^(2)`
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