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A particle starts moving rectillineraly ...

A particle starts moving rectillineraly at time `t = 0`, such that its velocity 'v' changes with time 't' according to the equation `v = t^(2) -t` where `t` is in seconds and `v` is in `m//s`. The time interval for which the particle retards is

A

`t lt 1//2`

B

`1//2 lt tlt 1`

C

`t gt 1`

D

`t lt 1//2` and `t gt 1`

Text Solution

Verified by Experts

The correct Answer is:
B
For particle to retard `v` and `a` must be of opposite sign
`v = t^(2) - t rArr v = t(t-1) rArr v is -ve` for `t lt 1`
`a = (dv)/(dt) rArr a = 2t - 1 rArr a is +ve` for `t gt (1)/(2)`
so particle will retard for `(1)/(2)lt t lt 1`
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