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A projectile is thorwn with a velocity o...

A projectile is thorwn with a velocity of `50ms^(-1)` at an angle of `53^(@)` with the horizontal
The equation of the trajectroy is given by

A

`180y = 240x - x^(2)`

B

`180y = x^(2) -240x`

C

`180y = 135x - x^(2)`

D

`180y = x^(2) - 135x`

Text Solution

Verified by Experts

The correct Answer is:
A
`u_(x) = u cos theta = 30m//s, u_(y) = u sin theta = 40m//s`,
`tan theta = (4)/(3)`
`x = u cos theta t …(1)`
`y = usin theta t - (1)/(2) "gt"^(2) ….(2)`
From (1) & (2) `y = x tan theta - (1)/(2) (gx^(2))/((ucos theta)^(2))`
`y = (4)/(3) x- (gx^(2))/(2xx(30)^(2))rArr y = (4)/(3) x- (gx^(2))/(1800)`
`rArr y = (4x)/(3) - (x^(2))/(180)`
`180y = 240 x - x^(2)`
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