A ball starts from rest and accelerates at `0.500m//s^(2)` while moving downan inclied plane `9.00 m` long. When it reaches the bottom, the balls rolls up another plane, where, after moving `15.0m`, it comes to rest.

Options

A. What is the speed of the ball at the bottom of the first plane?
B. How long does it take to roall down the first plane?
C. What is the acceleration along the second plane?
D. What is the ball's speed after moving through

Answer

(a) `3m//s` (b) `6sec`. (c ) `-0.3 m//s^(2)` (d) `2.05 m//s`

Explanation

(a) `v^(2) = u^(2) +2as rArr v = sqrt(2as)`
`v = sqrt(2xx0.5 xx 9) rArr v = 3m//s`
(b) `s = ut +(1)/(2) at^(2) rArr 9 = (1)/(2) xx (0.5) xx t^(2)`
`rArr t = 6sec`
(c ) `v^(2) =u6(2) +2as rArr 0^(2) = 3^(2) +2 xx a xx 15`
`rArr a =- 0.3 m//s^(2)`
(d) `v^(2) = u^(2) +2as rArr v^(2) = 3^(2) +2 xx -0.3 xx 8`
`rArr v = sqrt(42.2)m//s rArr v = 2.05 m//s`