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A ball is projected on smooth inclined p...

A ball is projected on smooth inclined plane in direction perpendicular to line of greatest slope with velcoity of `8m//s`. Find it's speed after `1sec`.

Text Solution

Verified by Experts

The correct Answer is:
`10 m//s`
component of `g _|_` to velcoity is `g sin 37^(@)`
`v_(x) = 8m//s`
`v_(y) = g sin 37^(@) t`
`rArr v_(y) = 10 xx 0.6 xx 1`
`rArr v_(y) = 6m//s`
`v = sqrt(v_(x)^(2) +v_(y)^(2))`
`rArr v = sqrt((8)^(2)+(6)^(2)) rArr v = 10m/s`
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Knowledge Check

  • A particle is projected up a smooth inclined plane of inclination 60^(@) along the line of greatest slope. If it comes to instantaneous rest after 2 seconds, then the velocity of projection is ( g = 9.8 m//"sec"^(2) )

    A
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    B
    `10 m//s`
    C
    `16.97 m//s`
    D
    `19.6 m//s`

  • A small ball is projected up a smooth inclined plane with an initial speed of 10 m//s along the direction at 30^(@) to the bottom edge of the slope. It returns to the edge after 2s. The ball is in constant with the inclined plane throughout the process. What is the inclination angle of the plane?

    A
    `15^(@)`
    B
    `60^(@)`
    C
    `37^(@)`
    D
    `30^(@)`

  • A small ball is projected up a smooth inclined plane with an initial speed of 10 m//s along the direction at 30^(@) to the bottom edge of the slope .It returns to the edge after 2 s . The ball is in contact with the inclied plane throughout the process. The angle of inclination theta is :- .

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    B
    `53^(@)`
    C
    `30^(@)`
    D
    `37^(@)`

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