Find range of projectile on the inclined plane which is projected perpendicular to the incline plane with velcoity `20m//s` as shwon in figure.

Answer

`75m`

Explanation

given that `u_(x) = 0, u_(y) = 20m//s`
`a_(x) = g sin 37^(@), a_(y) =- g cos 37^(@) m//s^(2)`
for time of flight
`y = y_(0) +u_(y)t +(1)/(2)a_(y)t^(2)`
`0 = 0 + 20 t +(1)/(2) (-g cos 37^(@))t^(2)`

`0 = 20t - 4t^(2) rArr 0 = 4t (5-t) rArr t = 5sec`
for range `x = x_(0) +u_(x) t +(1)/(2) a_(x)t^(2)`
`R = (1)/(2)xx g sin 37^(@) xx (5)^(2)`
`R = (1)/(2) xx 6 xx 28 rArr R = 75 m`.