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A stone is dropped from a height h simul...

A stone is dropped from a height h simultaneously another stone is thrown up from the ground with such a velocity so that it can reach a height of 4h. The time when two stones cross each other is `sqrt(((h)/(kg)))` where `k = "_____"`

Text Solution

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The correct Answer is:
`sqrt(((h)/(8g)))`

velocity of projection of stone form ground
`0 = u^(2) - 2g xx 4h`
`u - sqrt(8gh)`
Let they cros at point `P`
for stone dropped from height `h`

`y = h - (1)/(2)g t^(2) ..(1)`
for stone thrown vertically upward from ground
`h = sqrt(8gh)t - (1)/(2) g t^(2) ..(2)`
from (1) & (2) `h = sqrt(8gh)t rArr t = sqrt((h)/(8g))`
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