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The block B moves with a velcoity u rela...

The block `B` moves with a velcoity `u` relative to the wedge `A`. If the velocity of the wedge is `v` as shown in figure, what is the value of `theta` so that the block `B` moves vertically as seen from ground.

Text Solution

Verified by Experts

The correct Answer is:
`cos^(-2) ((v)/(u))`

`-u cos theta hati +u sin theta hatj = vecV_(B//G) - vecV_(W//G)`
`-u cos theta hati +u sin theta hatj = vecV_(B//G) - vhati`
`(v- u cos theta) hati +usin theta hatj = vecV_(B//G)`
from given condition
`v - u cos theta = 0 rArr v = u cos theta`
`cos theta = (v)/(u) rArr theta = cos^(-1) (v)/(u)`
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