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A projectile si thrown with velocity of ...

A projectile si thrown with velocity of `50m//s` towards an inclined plane from ground such that is strikes the inclined plane perpendiclularly. The angle of projection of the projectile is `53^(@)` with the horizontal and the inclined plane is inclined at an angle of `45^(@)` to the horizonta..

(a) Find the time of flight.
(b) Find the distance between the point of projection and the foot of inclined plane.

Text Solution

Verified by Experts

The correct Answer is:
(a) `t = 7 sec`, (b) `175 m`
`v_(x) = u_(x) = 50 cos 53^(@) = 30m//s`
at striking point `v_(y) =- u_(x) =- 30 m//s`
(a) form time of flight
`v_(y) = u_(y) +a_(y) t rArr -30 = 40 +(-10)t rArr t = 7 sec` ltbrltgt (b) for distance
distance `= OQ - MQ = u_(x)t - (u_(y)t +(1)/(2)a_(y)t^(2))`
distance `= 30 xx 7- [40 xx 7 +(1)/(2) xx (-10) xx 7^(2)]`
distance `= 210 - (280 - 245) rArr distance `= 175 m`
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