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A particle moves in a straight line wit...

A particle moves in a straight line with retardatino proportional it its displacement. Calculate the loss of `K.E.` for any displacement `x`.

A

`x^(2)`

B

`e^(x)`

C

`x`

D

`log_(e)x`

Text Solution

Verified by Experts

The correct Answer is:
A
`-(vdv)/(dx) = Cx`
`-int_(u)^(v) vdv = overset(x_(2))underset(x_(1))int Cxdx`
`(u^(2)-v^(2))/(2) = (Cx^(2))/(2)`
`m((u^(2)-v^(2))/(2)) = (mCx^(2))/(2)`
Loss of `KE prop x^(2)`
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