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The velcity of a paarticle is given by v...

The velcity of a paarticle is given by v=u_(0) + gt+ 1/2 ft^(2). If its position is `x =0` at `t=0`, then what is its displacement after `t=1 s` ?

A

`v_(0) +g//2+f`

B

`v_(0) +2 g+3f`

C

`v_(0) +g//2 +f//3`

D

`v_(0) +g +f`

Text Solution

Verified by Experts

The correct Answer is:
C
`v = v_(0) +g t +ft^(2)`
or `(dx)/(dt) = v_(0) +g t +ft^(2)`
`rArr dx = (v_(0) +gt +ft^(2)) dt`
So, `int_(0)^(x) dx = int_(0)^(1) (v_(0) +gt +ft^(2))dt`
`rArr x = v_(0) +(g)/(2) +(f)/(3)`
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