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For a particle in uniform circular motio...

For a particle in uniform circular motion , the acceleration ` vec(a)` at a point ` p ( R, theta )` on the circle of radiu ` R` is ( Here ` theta` is measured from the ` x- axis` )

A

`(v^(2))/(R )hati +(v^(2))/(R ) hatj`

B

`-(v^(2))/(R ) cos theta hati +(v^(2))/(R ) sin theta hatj`

C

`-(v^(2))/(R ) sin theta hati +(v^(2))/(R ) cos theta hatj`

D

`-(v^(2))/(R ) cos theta hati - (v^(2))/(R ) sin theta hatj`

Text Solution

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The correct Answer is:
D

`a_(C) =- (V^(2))/(R ) cos theta hati - (V^(2))/(R ) sin theta hatj`
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