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A boy playing on the roof of a 10 m high...

A boy playing on the roof of a `10 m` high building throws a ball with a speed of `10 m//s^(-1)` at an angle of `30^(@)` with the horizontal. How far from the throwing point will the ball be at a height of `10 m` from the ground?

A

`5.20 m`

B

`4.33 m`

C

`2.60 m`

D

`8.66 m`

Text Solution

Verified by Experts

The correct Answer is:
D
`R = (u^(2)sin 2 theta)/(g) = (10 xx 10 xx sin 60^(@))/(10) = 10 xx (sqrt(3))/(2)`
`= 5 xx 1.732 = 8.66 m`
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