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A particle of mass 'm' is projected with...

A particle of mass 'm' is projected with a velocity `upsilon` making an angle of `30^(@)` with the horizontal. The magnitude of angular moment of the projectile about the point of projection when the particle is at its maximum height 'h' is

A

zero

B

`(mv^(3))/(sqrt(2)g)`

C

`(sqrt(13))/(16)(mv^(3))/(g)`

D

`(sqrt(3))/(2)(mv^(3))/(g)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(dv)/(dt) =- 2.5 overset(t)underset(0)int dt`
`overset(0)underset(6.25)int (dv)/(sqrt(v)) = - 2.5 overset(t)underset(0)int dt`
Solving we get `t = 1s`
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