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A horizontal force F = mg//3 is applied ...

A horizontal force `F = mg//3` is applied on the surface of a uniform cube of mass 'm' and side 'a' which is resting on a rough horizontal surface having `mu_(S) = 1//2`. The distance between lines of action of 'mg' and normal reactiom 'N' is -

A

`a//2`

B

`a//3`

C

`a//4`

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
Since `F_(l) gt F` so `F_(r) = F rArr F_(r) = (mg)/(3)`
Balancing moment of force about `c.m.cw(+)`
`F xx (a)/(2) + F_(r) xx (a)/(2) = N xx x`

`2 xx (mg)/(3) xx (a)/(2) = mg xx x`
`x = (a)/(3)`.
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