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A uniform flag pole of length L and mass...

A uniform flag pole of length `L `and mass `M` in pivoted on the ground with a frictionless hinge. The flag pole makes an angle `theta` with the horizontal. The moment of inertia of the flag pole about one end is `(1//3) ML^(2)`. If starts falling from the position shown in figure, the linear acceleration of the free end of the flag pole-labeled `P` - would be.
.

A

`(2//3) g cos theta`

B

`(2//3) g`

C

`g`

D

`(3//2) g cos theta)`

Text Solution

Verified by Experts

The correct Answer is:
D
`tau = I alpha`
`r_(bot) F = I alpha`
`(L)/(2) cos theta xx mg = (mL^(2))/(3) alpha`
`L alpha = (3)/(2) g cos theta` since `a = r alpha`
`a = (3)/(2) g cos theta`.
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