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A rod of weight w is supported by two pa...

A rod of weight `w` is supported by two parallel knife edges `A` and `B` and is in equilibrium in a horizontal position. The knives are at a distance `d` from each other. The centre of mass of the rod is at a distance `x` from `A`.

A

the normal reaction at `A` is `(wx)/(d)`

B

the normal reaction at `A` is `(w(d - x))/(d)`

C

the normal reaction ar `B` is `(wx)/(d)`

D

the normal reaction at `B` is `(w(d - x))/(d)`.

Text Solution

Verified by Experts

The correct Answer is:
B, C

For `N_(1)`
Taking torque about `B`
`N_(1) d- w (d - x) = 0 rArr N_(1) = (w(d -x))/(d)`
For `N_(2)`
`wx - N_(2) d = 0, N_(2) = (wx)/(d)`.
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Knowledge Check

  • A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position . The knives are at a distance d from each other . The centre of mass of the rod is at distance x from A . The normal reaction on A is

    A
    `(W(d- x))/(x)`
    B
    `(W( d - x))/(d)`
    C
    `(Wx)/(d)`
    D
    `(Wd)/(x)`

  • A uniform metre rod is bent into L shape with the bent arms at 90^@ to each other. The distance of the centre of mass from the bent point is

    A
    `L/(4sqrt(2))m`
    B
    `L/(2sqrt(2))m`
    C
    `L/(sqrt(2))m`
    D
    `L/(8sqrt(2))m`

  • A uniform rod of mass m and length L lies radialy on a disc rotating with angular speed omega in a horizontal plane about vertical axis passing thorugh centre of disc. The rod does not slip on the disc and the centre of the rod is at a distance 2L from the centre of the disc. them the kinetic energy of the rod is

    A
    `(49mL^(2) omega^(2))/24`
    B
    `2 m omega^(2) L^(2)`
    C
    `1/24 m omega^(2)L^(2)`
    D
    `(13 mL^(2)omega^(2))/24`

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