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A block with a square base measuring ax...

A block with a square base measuring axa and height `h`, is placed on an inclined place. The coefficient of friction is `m`. The angle of inclination `(theta)` of the plane is gradually increased. The block will.

A

topple before sliding if `mu gt (a)/(h)`

B

topple before sliding if `mu lt (a)/(h)`

C

slide before toppling if `mu gt (a)/(h)`

D

slide before toppling if `mu lt (a)/(h)`

Text Solution

Verified by Experts

The correct Answer is:
A, D


For topping before sliding
From translational equilibrium
`f_(l) gt mg sin theta`
`mu mg cos theta mg sin theta`
`mu gt tan theta`…(1)
taking rotation torque about `N` to topple
`mg sin theta xx (h)/(2) gt mg cos theta xx (a)/(2) rArr tan theta gt (a)/(h)` ....(2)
From (1) and (2) `mu gt (a)/(h)`
For slide before toppling
for translatinal motion
`mg sin theta gt mu mg cos theta tan theta gt mu` ...(1)
`mg cos theta xx (a)/(2) gt mg sin theta xx (h)/(2) rArr (2)/(h) gt tan theta` ...(2)
From (1) and (2) `(a)/(h) gt mu` or `mu lt (a)/(h)`.
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A block of mass m is placed on a rough inclined plane. The corfficient of friction between the block and the plane is mu and the inclination of the plane is theta .Initially theta=0 and the block will remain stationary on the plane. Now the inclination theta is gradually increased . The block presses theinclined plane with a force mgcostheta . So welding strength between the block and inclined is mumgcostheta , and the pulling forces is mgsintheta . As soon as the pulling force is greater than the welding strength, the welding breaks and the blocks starts sliding, the angle theta for which the block start sliding is called angle of repose (lamda) . During the contact, two contact forces are acting between the block and the inclined plane. The pressing reaction (Normal reaction) and the shear reaction (frictional force). The net contact force will be resultant of both. Answer the following questions based on above comprehension: Q. For what value of theta will the block slide on the inclined plane:

A block of mass m is placed on a rough inclined plane. The corfficient of friction between the block and the plane is mu and the inclination of the plane is theta .Initially theta=0 and the block will remain stationary on the plane. Now the inclination theta is gradually increased . The block presses theinclined plane with a force mgcostheta . So welding strength between the block and inclined is mumgcostheta , and the pulling forces is mgsintheta . As soon as the pulling force is greater than the welding strength, the welding breaks and the blocks starts sliding, the angle theta for which the block start sliding is called angle of repose (lamda) . During the contact, two contact forces are acting between the block and the inclined plane. The pressing reaction (Normal reaction) and the shear reaction (frictional force). The net contact force will be resultant of both. Answer the following questions based on above comprehension: Q. If the entire system, were accelerated upward with acceleration a the angle of repose, would: