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A ring of mass M and radius R sliding wi...

A ring of mass `M` and radius `R` sliding with a velocity `v_(0)` suddenly enters inthrough surface where the coefficient of friction is `mu`, as shown in figure.
.
Choose the correct statement (s).

A

As the ring enters on the rough surface, the limiting friction force acts on it.

B

The direction of friction is opposite to the direction of motion

C

The friction force accelerated the ring in the clockwise sense about its centre of mass

D

As the ring enter on the rough surface it starts rolling.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C

(A) Since at the time of entering the rough surface it will have forward sliding so limiting friction will act.
(B) It is having forward sliding so friction is opposite to direction of motion
( C) Due to friction force it will have a torque is clockwise direction
(D) it will have rolling after some time.
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Knowledge Check

  • A ring of mass m sliding on a smooth surface with velocity v_(0) enters rough surface with coefficient of kinetic friction mu_(k) , then

    A
    the linear distance moved by centre of mass before the ring starts pure rolling is `(3v_(0)^(2))/(8 mu_(k)g)`
    B
    the gain in kinetic energy is `(mv_(0)^(2))/(8)`
    C
    the loss in kinetic energy is `(mv_(0)^(2))/(4)`
    D
    the work done by friction force is `-(3mv_(0)^(2))/(8)`

  • A solid cylinder of mass M and radius R pure rolls on a rough surface as shown in the figure. Choose the correct alternative (s).

    A
    The acceleration of the centre of mass is `F/(M)`
    B
    The acceleration of the centre of mass is `(2)/(3)F/(M)`
    C
    The friction force on the cylinder acts backward
    D
    The magnitude of the friction force is `F/(3)`

  • A sphere of mass M and radius R is moving on a rough fixed surface, having coefficient of friction mu . as shown in Fig. It will attain a minimum linear velocity after time v_(0)gtomega_(0)R)

    A
    `v_(0)//mug`
    B
    `omega_(0)R//mug`
    C
    `2(v_(0)-omega_(0)R)//5mug`
    D
    `2(v_(0)-omega_(0)R)//7mug`

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