Home
Class 11
PHYSICS
Four point masses, each of value m, are ...

Four point masses, each of value `m`, are placed at the corners of square `ABCD` of side `l`. The moment of inertia of this system about an axis passing through `A` and parallel to `BD` is -

A

`2ml^(2)`

B

`sqrt(3) ml^(2)`

C

`3 ml^(2)`

D

`ml^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`I = 2m (l//sqrt(2))^(2) + m(sqrt(2) l)^(2) = 3 ml^(2)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Four point masses, each of value m, are placed at the corners of a square ABCD of side l. The moment of inertia of this system about an axis passing through A and parallel to BD is

Four point masses, each of value m, are placed at the corners of a squre ABCD of side l. The moment of inertia of the is system about an axis passing through A and parallel to BD is

Four point masses, each of value m, are placed at the corners of a square ABCD, having each side of length L. What is the moment of inertia of this system about an axis passing through A and parallel to the diagonal BD?

Four equal masses, m each are placed at the corners of a square of length (l) as shown in the figure. The moment of inertia of the system about an axis passing through A and parallel to DB would be:

Three point masses each of mass m are placed at the corners of an equilateral triangle of side 'a' . Then the moment of inertia of this system about an axis passing along one side of the triangle is

Three point masses each of mass m are placed at the corners of an equilateral triangle of side 'a'. Then the moment of inertia of this system about an axis passing along one side of the triangle is