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A hoop of radius r mass m rotating with ...

A hoop of radius `r` mass `m` rotating with an angular velocity `omega_(0)` is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it cases to slip ?

A

`(r omega_(0))/(2)`

B

`r omega_(0)`

C

`(r omega_(0))/(4)`

D

`(r omega_(0))/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`C.O.A.M` (about bottom)
`mr^(2) omega_(0) = 2mr^(2) (v_(cm))/( r)`
`v_(cm) = (omega_(0) r)/(2)`.
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