A particle moves in circular path with d...

A particle moves in circular path with decreasing speed. Which of the following is correct.

A

`vec L` is constant

B

only direction of `vec L` is constant

C

acceleration `vec a` is towards the centre

D

it will move in a spiral and finally reach the centre

Verified by Experts

The correct Answer is:

B

`vec L = m(vec r xx vec v)`
Direction of `(vec r xx vec v)` is constant, hence the direction of angular momentum remains the same.

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