Home
Class 11
PHYSICS
The displacement of a body executing SHM...

The displacement of a body executing `SHM` is given by `x=A sin (2pit+pi//3)`. The firs time from `t=0` when the velocity is maximum is

A

`0.33 sec`

B

`0.16sec`

C

`0.25 sec`

D

`0.5 sec`

Text Solution

Verified by Experts

The correct Answer is:
A
Figure
Promotional Banner

Similar Questions

Explore conceptually related problems

The displacement of a body executing SHM is given by x=lambdasin(2pit+pi//3) . The first time from t = 0 when the velocity is maximum is :

The displacement of a body executing SHM is given by x=Asin(2pit+pi//6) . The first time from t = 0 when the velocity is maximum is :

The displacement of a particle executing S.H.M is given by x= 0.01 sin 100pi (t + 0.05) . The time period is

The displacement of a particle executing S.H.M. is x = 5 sin (20 pit ). Then its frequency will be

The displacement of a particle executing S.H.M. is given by x = 0.34 sin (300 t + 0.68)m. Then its frequency is

If the displacement of a particle executing SHM is given by y=0.30 sin (220t +0.64) in metre , then the frequency and maximum velocity of the particle is

The displacement of a particle executing SHM is given by Y=5 " sin "(4t+(pi)/(3)) If T is the time period and the mass of the particle is 2g, the kinetic energy of the particle When t= (T)/(4) is given by-

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200t cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The equation for the displacement of a particle executing SHM is x = 5sin (2pit)cm Then the velocity at 3cm from the mean position is( in cm//s)