Home
Class 11
PHYSICS
A particle executes SHM on a straight li...

A particle executes SHM on a straight line path. The amplitude of oscillation is `2cm`. When the displacement of the particle from the mean position is `1cm`, the numerical value of magnitude of acceleration is equal to the mumerical value of velocity. Find the frequency of SHM (in `Hz`).

A

`2pisqrt(3)`

B

`(2pi)/(sqrt(3))`

C

`(sqrt3)/(2pi)`

D

`(1)/(2pisqrt3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle executes SHM in a straight line path .The amplitude of oscillation is 2cm . When the displacement of the particle from the mean position is 1cm the numerical value of acceleration is equal to the numerical value of velocity. Then find the frequency of SHM .

A partical executes SHM on a straigh line path. The amplitude of oscillation is 2cm. When the displacement of the particle from the mean position is 1cm, the magnitude of its acceleration is equal to that of its velocity. Find the time period of SHM, also the ms. velocity and ms. acceleration of SHM.

A particle executes SHM on a straight line path. The amplitude of oscillation is 3 cm. Magnitude of its acceleration is eqal to that of its velocity when its displacement from the mean position is 1 cm. Find the time period of S.H.M.

A particle describes SHM along a straight line with a period of 2 s and amplitude 10 cm. Its velocity when it is at a distance of 6 cm from mean position is

A particle executes SHM on a straight line path. The amplitude of oscialltion is 3 cm. Magnitude of its acceleration is eqal to that of its velocity when its displacement from the mean position is 1 cm. Find the time period of S.H.M. Hint : A= 3cm When x=1 cm , magnitude of velocity = magnitude of acceleration i.e., omega(A^(2) - x^(2))((1)/(2)) = omega^(2) x Find omega T = ( 2pi)(omega)

A particle is executing SHM of amplitude 10 cm. Its time period of oscillation is pi seconds. The velocity of the particle when it is 2 cm from extreme position is

A particle executes SHM with a time period of 2 s and amplitude 5 cm. What will be the displacement and velocity of that particle at t = 1/3 ?

A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A particle executes linear simple harmonic motion with an amplitude of 3 cm . When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is