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Two particle execute SHM with amplitude ...

Two particle execute `SHM` with amplitude `A` and `2A` and angular frequency `omega` and `2omega` repectively. At `t=0` they starts with some initial phase difference. At, `t=(2pi)/(3omega)`. They are in same phase. Their initial phase difference is-

A

`(pi)/(3)`

B

`(2pi)/(3)`

C

`(4pi)/(3)`

D

`pi`

Text Solution

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The correct Answer is:
B, C
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