Home
Class 11
PHYSICS
A force F=-10x+2 acts on a particle of m...

A force F=-10x+2 acts on a particle of mass 0.1 kg where m is m and F is in newtons. If F is released from rest at x=0, find:
a. amplitude:
b. time period:
c. equation of motion.

Text Solution

Verified by Experts

The correct Answer is:
`(11)/(5)m,(b)(pi)/(5)sec.,(c )X=0.2-(11)/(5)cosomegat`
Figure
Promotional Banner

Similar Questions

Explore conceptually related problems

A force F = - 10x + 2 acts on a particle of mass 0.1 kg where x is in m and F in newton. If is released from rest at x = 0 , find: a. Amplitude: b. Time period: c. Equation of motion.

A force F = Be^(Ct) acts on a particle whose mass is m and whose velocity is 0 at t = 0. It's terminal velocity is :

Passage XII)_ A particle of mass m is constrained to move along x-axis. A force F acts on the particle. F always points toward the position labelled E. For example, when the particle is to the left of E,Fpoints to the right. The magnitude of F is consant except at point E where it is zero. The systm is horizontal. F is the net force acting on the particle. the particle is displaced a distance A towards left from the equilibrium position E and released from rest at t=0. What it is the time period of periodic motion of particle.

A particle is moving on y axis under a varible force F= - ky + C . If in part (a) F= - 10y + 20 , and mass m of the particle is 2.5kg and it is released from rest from y = +3 , at t= 0, write the equation of SHM.

A force F=(2+x) acts on a particle in x-direction where F is in newton and x in metre. Find the work done by this force during a displacement form 1. 0 m to x = 2.0 m.

A force F=(15+0.50x) acts on a particle in the X-direction ,where F is in newton and x in metre Find the work done ' by this force during a displacement from x=0 to x=2.0 m .

A force F=(10+0.50x) acts on a particle in the x direction, where F is in newton and x in meter./find the work done by this force during a displacement form x=0 tox=2.0m

A force F=(5+2x) acts on a particle in x direction where F is in newtown and x is meter. Find the work done by this force during displacement from x=0 to x=1m.

A force F=20+10y acts on a particle in y-direction where F is in Newton and y in meter. Wrok done by this force to move the particle from y=0 to y=1 m is:

A force F = 0.5x + 10 acts on a particle. Here F is in newton and x is in metre. Calculate the work done by the force during the displacement of the particle from x = 0 to x = 2 metre.