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The equation of a particle executing SHM...

The equation of a particle executing `SHM` is `(d^(2)x)/(dt^(2))=-omega^(2)x`. Where `omega=(2pi)/("time period")`. The velocity of particle is maximum when it passes through mean position and its accleration is maximum at extremeposition. The displacement of particle is given by `x=A sin(omegat+theta)` where `theta`-initial phase of motion. `A`-Amplitude of motion and T-Time period
The time period of pendulum is given by the equation `T=2pisqrt((l)/(g))`. Here`(d^(2)x)/(dt^(2))` is :

A

`(-l)/(g)x`

B

`(g)/(l)x`

C

`(1)/(g)x`

D

`(-g)/(l)x`

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The correct Answer is:
A
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