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The equation of a particle executing SHM...

The equation of a particle executing `SHM` is `(d^(2)x)/(dt^(2))=-omega^(2)x`. Where `omega=(2pi)/("time period")`. The velocity of particle is maximum when it passes through mean position and its accleration is maximum at extremeposition. The displacement of particle is given by `x=A sin(omegat+theta)` where `theta`-initial phase of motion. `A`-Amplitude of motion and T-Time period
The accleration is half of its maximum value at an amplitude of

A

`(A)/(sqrt2)`

B

`(sqrt3A)/(2)`

C

`(A)/(sqrt3)`

D

`(A)/(2)`

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The correct Answer is:
D
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