If `sqrt(9-(n-2)^2)` is a real number, then the number of integral values of n is

If N^(2)-33, N^(2)-31 and N^(2)-29 are prime numbers, then what is the number of possible values of N, where N is an integer?

If a_1,a_2 …. a_n are positive real numbers whose product is a fixed real number c, then the minimum value of 1+a_1 +a_2 +….. + a_(n-1) + a_n is :

If a_1,a_2 …. a_n are positive real numbers whose product is a fixed real number c, then the minimum value of 1+a_1 +a_2 +….. + a_(n-1) + a_n is :

If n is a such real number that n>3 .then n^2>9 prove it by the method of contradiction.

For some natural number N, the number of positive integral 'x' satisfying the equation, 1! +2!+ 3!+.............(x!)=(N)^2 is

For some natural number N, the number of positive integral 'x' satisfying the equation, 1! +2!+ 3!+.............(x!)=(N)^2 is

For some natural number N ,the number of positive integral 'x' satisfying the equation,1!+2!+3!+.........(x!)=(N)^(2) is

If [x] denotes the integral part of x and n is a natural number such that 1<=n<100 then the number of solutions of the equation [(n)/(2)]+[(n)/(3)]+[(n)/(5)]=(n)/(2)+(n)/(3)+(n)/(5) is

The number of integral coordinates of the points (x, y) which are lying inside the circle x^(2) + y^(2) = 25 is n, then the integer value of (n)/(9) will be -