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A simple pendulum has time period (T1). ...

A simple pendulum has time period (T_1). The point of suspension is now moved upward according to the relation `y = K t^2, (K = 1 m//s^2)` where (y) is the vertical displacement. The time period now becomes (T_2). The ratio of `(T_1^2)/(T_2^2)` is `(g = 10 m//s^2)`.

A

`5//6`

B

`11//10`

C

`6//5`

D

`5//4`

Text Solution

Verified by Experts

The correct Answer is:
C
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