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The mass and diameter of a planet are tw...

The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If it is a 2 second's pendulum on earth?

A

`sqrt(2)` second

B

`2sqrt(2)` second

C

`1/(sqrt(2))` second

D

`1/(2sqrt(2))` second

Text Solution

Verified by Experts

The correct Answer is:
b
`g=(GM)/(R^(2)) & g'=(G(2M))/((2R)^(2))`
so `g'=g/2`
`T'=2pisqrt(l/(g'))impliesT'=2pisqrt((2l)/g)`
`T'=sqrt(2)TimpliesT'=2sqrt(2)sec`.
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