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Two point masses of mass 4m and m respec...

Two point masses of mass `4m` and `m` respectively separated by `d` distance are revolving under mutual force of attraction. Ration of their kinetic energies will be:

A

`1:4`

B

`1:5`

C

`1:1`

D

`1:2`

Text Solution

Verified by Experts

The correct Answer is:
a
They will revolue about this centre of mass position of centre of mass
`0=4m(-x)+m(d-x)`
`x=d/5`
They will same ` omega`
`(K_(4m))/(K_(m))=(1/2I_(4m)omega^(2))/(1/2I_(m)omega^(2))`
`(K_(4m))/(K_(m))=(1/2(4m)(d//5)^(2))/(1/2(m)(4d//5)^(2))implies(K_(4m))/(K_(m))=1/4`
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