Home
Class 11
PHYSICS
A satallite of mass m, initally at rest ...

A satallite of mass `m`, initally at rest on the earth, is launched into a circular orbit at a height equal to the the radius of the earth. The minimum energy required is

A

`(sqrt(3))/4 mgR`

B

`1/2 mgR`

C

`1/4 mgR`

D

`3/4 mgR`

Text Solution

Verified by Experts

The correct Answer is:
d

We know
`V_(0)=sqrt((GM)/r) & g=(GM)/(R^(2))`
From energy conservation
`U_(i)+K_(i)=U_(f)+K_(f)`
`-(GMm)/(2R)+1/2m(sqrt((GM)/(2R)))^(2)`
`K_(i)=(3GMm)/(4R)impliesK_(i)=3/4 mgR`
Promotional Banner

Similar Questions

Explore conceptually related problems

A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by

A satellite of mass m is Launched from the earth's surface in a circular orbit. If M and R denote the mas and radius of the earth respectively, then the total energy of the satellite at an altitude 2R is

A skylab of mass m kg is first launched from the surface of the earth in a circular orbit of radius 2R (from the centre of the earth) and then it is shifted from this circular orbit to another circular orbit of radius 3R . The minimum energy required to place the lab in the first orbit and to shift the lab from first orbit to the second orbit are

A body of mass m taken from the earth's surface to the height equal to the twice the earth radius R of the earth . The change in potential energy of the body will be

A body of mass m taken form the earth's surface to the height is equal to twice the radius (R) of the earth. The change in potential energy of body will be

A body of mass m is taken from the earth's surface to the height equal to twice the radius (R) of the earth.The change in potential energy of body will be