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Two masses m(1) and m(2)(m(1)ltm(2)) are...

Two masses `m_(1)` and `m_(2)(m_(1)ltm_(2))` are released from rest finite distance. They start under their mutual gravitational attraction-

A

acceleration of `m_(1)` is more than that of `m_(2)`

B

acceleration of `m_(2)` is more than that of `m_(1)`

C

centre of mass of system will remain at rest in all the references frame.

D

total energy of system remains constant

Text Solution

Verified by Experts

The correct Answer is:
a,d

(A) `a_(1)=(f_(g))/(m_(1))` and `a_(2)=(f_(g))/(m_(2))` since `m_(1)ltm_(2)` so `a_(1)gt a_(2)`
(D) total energy of system remains constant. So choice `(A)` and `(D)` are correct.
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