An object of length `1`cm is placed at a distance of`15cm`from a concave mirror of focal length`10cm`.The nature and size of the image are-
(1) real,inverted,`1.0cm` ,(2)real, inverted,`2.0cm`
,(3)virtual ,erect,`0.5cm` (4) virtual ,erect,`1.0cm`

Explanation

To solve the problem, we will use the mirror formula and the magnification formula. Let's go through the steps one by one.

### Step 1: Identify the given values
- Object length (h) = 1 cm
- Object distance (u) = -15 cm (negative as per sign convention for concave mirrors)
- Focal length (f) = -10 cm (negative for concave mirrors)

### Step 2: Use the mirror formula
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