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Diameter of the moon is 3.5xx10^(3)kmand...

Diameter of the moon is `3.5xx10^(3)km`and its distance from earth is`3.8xx10^(5)km`.It is seen by a telescope whose objectives and eyepiece have focal lengths`4`mand `10cm`respectively.The angular diameter fo the image of the moon will be nearly-
(1) `5^(@)` ,(2) `10^(@)` ,(3)` 20^(@)` ,(4)`25^(@)`

Text Solution

Verified by Experts

`M=-(f_(0))/(f_(e))=-(400)/(10)-40`
Angle substanded by the moon at the objective
` =(3.5xx10^(3))/(3.8xx10^(5))=0.009 radian`
Thus the angular diameter of the image
`=Mxx"visual angle"`
`=40xx0.009=0.36radian`
`=(0.36xx180)/(3.14)=20^(@)`
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