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The reflecting surface of a plane mirror...

The reflecting surface of a plane mirror is vertical. A particle is projected in a vertical plane which is also perpendicular to the mirror. The initial speed of the particle is `10m//s` and the angle of projection is `60^@` from the normal of the mirror. The point of projection is at a distance 5m from the mirror. The particle moves towards the mirror. Just before the particle touches the mirror, the velocity of approach of the particle and the image is:

A

`10m//s`

B

`5m//s`

C

`10sqrt(3)m//s`

D

`5sqrt(3)m//s`

Text Solution

Verified by Experts

The correct Answer is:
A

`(V_(I//M))_(_|_)=-(V_(O //M))_|_`
`(V_(I//M))_(11)=(V_(O //M))_(11)`
so`(V_(I //O))=2(V_(I//M))_(_|_)`
`(V_(I//O))=10m//s`
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