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The figure shows a ray incident a angle ...

The figure shows a ray incident a angle `i=pi//3` of the plot drawn shown the variartion of `|r-i|`versus`(mu_(1))/(mu_(2))`=k,`(r="angle of refraction")`

the value of`theta_(1)`

A

the value of`k_(1)`is`(2)/(sqrt(3))`

B

the value of`theta_(1)=pi//6`

C

the value of`theta_(2)=pi//3`

D

the value of`k_(2)`is`1`

Text Solution

Verified by Experts

The correct Answer is:
B,C,D
(B) at `theta_(1)` deviation is max so `r=90^(@)=pi//2`
`r-i=theta_(1) rArr theta_(1)=pi//2-pi//3 implies theta_(1) = pi/6`
(C ) at `theta_(2)` deviation is max.so r= 0
`r-i=theta_(2) rArr theta=pi//3`
(d) at `k_(2)`deviation is `0` so `mu_(1)=mu_(2)` therefore `k_(2)=1`
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