Home
Class 11
PHYSICS
STATEMENT-1 The focla lengh of a lens do...

STATEMENT-`1` The focla lengh of a lens does not depend on the medium in which it is submerged.
`STATEMENT 2 (1)/(f)=(mu_(2)-mu_(1))/(mu_(1))((1)/(R_(1))-(1)/(R_(2)))`

A

STATEMENT -`1`is true statement `2` is true,Statement -`2`is a correct explanation for statement -`1`

B

STATEMENT -`1`is true statement `2` is true,Statement -`2`is a not a correct explanation for statement -`1`

C

Statement -`1`is true,Statement -`2`is False

D

Statement -`1`is False ,Statement -`2`is True

Text Solution

Verified by Experts

The correct Answer is:
D
AS can be seen from the expression of `f`,it depends upon the refractive index of the medium which the lens is submerged.
Promotional Banner

Similar Questions

Explore conceptually related problems

Assertion : A double convex lens (mu=1.5) has focal length 10 cm . When the lens is immersed in water (mu=4//3) its focal length becomes 40 cm . Reason : (1)/(f)=(mu_(1)-mu_(m))/(mu_(m))((1)/(R_(1))-(1)/(R_(2)))

STATEMENT- 1 Power of a lens depends on nature of material of lens, medium in which it is placed and radii of curvature of its surface. STATEMENT 2 it follows the relation p=(1)/(f)=((mu_(2))/(mu_(1))-1)[(1)/(R_(1))-(1)/(R_(2))]

STATEMENT- 1 Air bubble in glass medium behaves as concave lens. STATEMENT 2 Lens formula is (1)/(f)=((mu_("lens"))/(mu_("med"))-1) [(1)/(R_(1))-(1)/(R_(2))]

Statement-1 : Focal length of an equiconvex lens of mu = 3//2 is equal to radius of curvature of each surface. Statement-2 : it follows from (1)/(f) = (mu - 1)((1)/(R_(1)) - (1)/(R_(2)))

Statement-1 : A glass convex lens (refractive index, mu_(1)=1.5 ), when immersed in a liquid of refractive index mu_(2)=2 , functions as a diverging lens. Statement-2 : The focal length of a lens is given by (1)/(f)=(mu-1)((1)/(R_(1))-(1)/(R_(2))) , where mu is the relative refractive index of the material of the lens with respect to the surrounding medium.

A point source of light is placed inside water and a thin converging lens ofrefractive index mu_(2) is placed just outside the plane surface of water. The image of the source is formed at a distance x from the surface of water. If the lens is now placed just inside water and the image is now formed at a distances' from the surface of water, show that (1)/(x) -(1)/(x_(1)) = (mu_(1)-1)/(mu_(2)-1) xx (1)/(f) , Where f is the focal length of the lens and mu_(1) is the refractive index of water.

Two transparent sheets of thickness t_(1) and t_(2) and refractive indexes mu_(1) and mu_(2) are placed infront of the slits in YDSE setup as shown in figure-6.47. If D is the distance of the screen from the slits, then find the distance of zero order maxima from the centre of the screen. What is the condition that zero order maxima is formed at the centre O? [(D[(mu_(1)-1)t_(1)-(mu_(2)-1)t_(2)])/(d),(mu_(2)-1)t_(2)]