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Wavelength of light used in an optical i...

Wavelength of light used in an optical instrument are `lambda_(1) = 4000 Å` and `lambda_(2) = 5000Å` then ratio of their respective resolving powers (corresponding to `lambda_(1)` and `lambda_(2)`) is

A

`16:25`

B

`9:1`

C

`4:5`

D

`5:4`

Text Solution

Verified by Experts

The correct Answer is:
4
Resolving power of an optical instruments is inversely proportional to`lambda`ie,
`RPprop(1)/(lambda)`
`:.("Resoving power at" lambda_(1))/("Resolving power at"lambda_(2)) =(lamda_(2))/(lambda_(1))`
`=(5000)/(4000)=5:4`
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