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[" 25."2sin A-cos^(3)A-2sin^(3)A-cos A" ...

[" 25."2sin A-cos^(3)A-2sin^(3)A-cos A" atlat "(1)/(6)],[[" (a) "1+2sin^(2)2x," (b) "(1)/(2)sin4A],[" (c) "1-8sin^(2)x*cos^(2)x," (d) "(1)/(2)tan4A]]

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sin^6A+cos^6A+3sin^2A.cos^2A=

sin^(6)A + cos^(6)A + 3sin^(2)A.cos^(2)A=

sin ^ (6) A + cos ^ (6) A = 1-3sin ^ (2) A cos ^ (2) A

Prove that sin^(6)x + cos^(6)x = 1 - 3 sin^(2) x cos^(2)x .

(sin^(2)3A)/(sin^(2)A)-(cos^(2) 3A)/(cos^(2)A)=

cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)

cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)

(sin^(2)3A)/(sin^2A)-(cos^(2)3A)/(cos^2A)=