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For the diffraction from a crystal with ...

For the diffraction from a crystal with `lamda=1Å` and Bragg's angle `theta=60^(@)`, then for the second order diffraction 'd' will be :

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Diffraction angle 2 theta equal to 14.8^@ for a crystal having interplanar distance in the crystal is 0.400 nm when second order diffraction was observed. Calculate the wavelength of X-ray used

Diffraction angle 2 theta equal to 14.8^@ for a crystal having interplanar distance in the crystal is 0.400 nm when second order diffraction was observed. Calculate the wavelength of X-ray used

Diffraction angle 2 theta equal to 14.8^@ for a crystal having interplanar distance in the crystal is 0.400 nm when second order diffraction was observed. Calculate the wavelength of X-ray used

Light is incident normally on a diffraction grating through which the first order diffraction is seen at 32^@ . The second order diffraction will be seen at

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Diffraction angle 2 theta equal to 14.8 ^(@) for a crystal having interplanar distance in the crystal is 0.400 nm when second order diffraction was observed. Calculate the wavelength of X-ray used.

Wave property of electron implies that they will show diffraction effected . Davisson and Germer demonstrated this by diffracting electron from crystals . The law governing the diffraction from a crystals is obtained by requiring that electron waves reflected from the planes of atoms in a crystal inter fere constructiely If a strong diffraction peak is observed when electrons are incident at an angle i from the normal to the crystal planes with distance d between them (see fig) de Brogle wavelength lambda_(dB) of electrons can be calculated by the relationship (n is an intenger)