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If the lies (x-3)/1=(y+2)/-1=(z+lambda)...

If the lies `(x-3)/1=(y+2)/-1=(z+lambda)/(-2)` lies on the line, `2x - 4y +3z= 2`, then the shortest distance between this line and the line, `(x-1)/12=y/9=z/4` is (A) 0 (B) 2 (C) 1 (D) 3

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