[" Q.17The radius of the circle circumscribing the triangle "ABC" ,is equal to "],[[" (A) "(sqrt(10))/(2)," (B) "sqrt(5)," (C) "sqrt(10)," (D) "(sqrt(5))/(2)]],[hline]

In triangle ABC let tanA=1, tanB= 2, tanC=3 and c= 3, The radius of the circle circumscribing the triangle ABC, is equal to A. (sqrt10)/(2) B. sqrt5 C. sqrt10 D. (sqrt5)/(2)

In triangle ABC let tanA=1, tanB= 2, tanC=3 and c= 3, The radius of the circle circumscribing the triangle ABC, is equal to A. (sqrt10)/(2) B. sqrt5 C. sqrt10 D. (sqrt5)/(2)

The radius of the circle passing through the vertices of the triangle ABC,is

The least area of a circle circumscribing any right triangle of area S is:

The least area of a circle circumscribing any right triangle of area S is:

The least area of a circle circumscribing any right triangle of area S is:

The least area of a circle circumscribing any right triangle of area S is:

The radius of the circle passing through the vertices of the triangle ABC, is

The least area of a circle circumscribing any right triangle of area (9)/(pi) is