A dimensionally consistent relation for the volume `V` of a liquid of coefficiet of viscosity `eta` flowing per second through a tube of radius `r` and length `l` and having a pressure difference `p` across its end, is

The volume of a liquid of density rho and viscosity eta flowing in time t through a capillary tube of length l and radius R, with a pressure difference P, across its ends is proportional to :

A liquid of coefficient of viscosity eta is flowing steadily through a capillary tube of radius r and length I. If V is volume of liquid flowing per sec. the pressure difference P at the end of tube is given by

Stoke's law states that the viscous drag force F experienced by a sphere of radius a, moving with a speed v through a fluid with coefficient of viscosity eta , is given by F=6 pi eta If this fluid is flowing through a cylindrical pipe of radius r, length l and a pressure difference of P across its two ends, then the volume of water V which flows through the pipe in time t can be written as (V)/(t)=K ((p)/(l))^(a)eta^(b)r^(c ) where k is a dimensionless constant. Correct values of a, b and c are -

Stoke’s law states that the viscous drag force F experienced by a sphere of radius a, moving with a speed V through a fluid with coefficient of viscosity eta , is given by F = 6pi"na"v . If this fluid is flowing through a cylindrical pipe of radius r, length l and a pressure difference of P across its two ends, then the volume of water V which flows through the pipe in time t can be written as c (V)/(t)=k((P)/(l))eta^(b)r^(c) , where k is a dimensional constant. Correct values of a, b and c are

When a viscous liquid flows , adjacent layers oppose their relative motion by applying a viscous force given by F = - eta A (dv)/(dz) where , ete = coefficient of viscosity , A = surface area of adjacent layers in contact , (dv)/(dz) = velocity gradient Now , a viscous liquid having coefficient of viscosity eta is flowing through a fixed tube of length l and radius R under a pressure difference P between the two ends of the tube . Now consider a cylindrical vloume of liquid of radius r . Due to steady flow , net force on the liquid in cylindrical vloume should be zero . - eta 2pirl (dv)/(dr) = Ppir^(2) - int _(v)^(0),dv = P/(2 eta l) int_(tau)^(R) rdr ( :' layer in contact with the tube is stationary ) v = v_(0) (1- (r^(2))/(R^(2))) , where v_(0) = (PR^(2))/(4nl) :. " " Q = (piPR^(4))/(8sta l) This is called Poisecuille's equation . The volume of the liquid flowing per sec across the cross - section of the tube is .

When a viscous liquid flows , adjacent layers oppose their relative motion by applying a viscous force given by F = - eta A (dv)/(dz) where , eta = coefficient of viscosity , A = surface area of adjacent layers in contact , (dv)/(dz) = velocity gradient Now , a viscous liquid having coefficient of viscosity eta is flowing through a fixed tube of length l and radius R under a pressure difference P between the two ends of the tube . Now consider a cylindrical vloume of liquid of radius r . Due to steady flow , net force on the liquid in cylindrical volume should be zero . - eta 2pirl (dv)/(dr) = Ppir^(2) - int _(v)^(0),dv = P/(2 eta l) int_(tau)^(R) rdr ( :' layer in contact with the tube is stationary ) v = v_(0) (1- (r^(2))/(R^(2))) , where v_(0) = (PR^(2))/(4nl) :. " " Q = (piPR^(4))/(8sta l) This is called Poisecuille's equation . The velocity of flow of liquid at r = R/2 is

volume rate flow of a liquid of density rho and coefficient of viscosity eta through a cylindrical tube of diameter D is Q. Reynold's number of the flow is

V is the volume of a liquid flowing per second through a capillary tube of length l and radius r, under a pressure difference (p). If the velocity (v), mass (M) and time (T) are taken as the fundamental quantities, then the dimensional formula for eta in the relation V=(pipr^(4))/(8etal)

The volume of a liquid flowing per second through a capillary tube under a constant pressure difference is directly proportional to the_________power of radius.